# Prime factorization of 428

Here you will see step by step solution of prime factorization of 428, how to find factors of 428, you will see all factors of 428, how many factors of 428 has? Factors of 428 are 1, 2, 4, 107, 214, 428, we can see that 428 has 6 factor and sum of all factors is 756.

• All Factors of 428: 1, 2, 4, 107, 214, 428
• Prime Factors of 428: 2 × 2 × 107
• Prime Factorization of 428: 22 × 1071
• Sum of Factors of 428: 756
• Is 428 prime number: No

### How to find factors of 428 by Division Method?

To find the factors of 428 by division method, we need the find the all numbers between 1 to 428, which divide 428 with 0 remainder, then the number is factor of 428.

### Pair factors of 428

• 428/1 = 428 [ 1 × 428 (1, 428) 1 and 428 is pair factor of 428]
• 428/2 = 214 [ 2 × 214 (2, 214) 2 and 214 is pair factor of 428]
• 428/4 = 107 [ 4 × 107 (4, 107) 4 and 107 is pair factor of 428]
• 428/107 = 4 [ 107 × 4 (107, 4) 107 and 4 is pair factor of 428]
• 428/214 = 2 [ 214 × 2 (214, 2) 214 and 2 is pair factor of 428]
• 428/428 = 1 [ 428 × 1 (428, 1) 428 and 1 is pair factor of 428]

As we checked numbers between 1 to 428 that are not leaving any remainder, hence we can say factors of 428 is 1, 2, 4, 107, 214, 428.

Also note that, in exponential form prime factorization of 428 is written as 22 × 1071 and it is a composite number.

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