# Prime factorization of 540

Here you will see step by step solution of prime factorization of 540, how to find factors of 540, you will see all factors of 540, how many factors of 540 has? Factors of 540 are 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270, 540, we can see that 540 has 24 factor and sum of all factors is 1680.

• All Factors of 540: 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270, 540
• Prime Factors of 540: 2 × 2 × 3 × 3 × 3 × 5
• Prime Factorization of 540: 22 × 33 × 51
• Sum of Factors of 540: 1680
• Is 540 prime number: No

### How to find factors of 540 by Division Method?

To find the factors of 540 by division method, we need the find the all numbers between 1 to 540, which divide 540 with 0 remainder, then the number is factor of 540.

### Pair factors of 540

• 540/1 = 540 [ 1 × 540 (1, 540) 1 and 540 is pair factor of 540]
• 540/2 = 270 [ 2 × 270 (2, 270) 2 and 270 is pair factor of 540]
• 540/3 = 180 [ 3 × 180 (3, 180) 3 and 180 is pair factor of 540]
• 540/4 = 135 [ 4 × 135 (4, 135) 4 and 135 is pair factor of 540]
• 540/5 = 108 [ 5 × 108 (5, 108) 5 and 108 is pair factor of 540]
• 540/6 = 90 [ 6 × 90 (6, 90) 6 and 90 is pair factor of 540]
• 540/9 = 60 [ 9 × 60 (9, 60) 9 and 60 is pair factor of 540]
• 540/10 = 54 [ 10 × 54 (10, 54) 10 and 54 is pair factor of 540]
• 540/12 = 45 [ 12 × 45 (12, 45) 12 and 45 is pair factor of 540]
• 540/15 = 36 [ 15 × 36 (15, 36) 15 and 36 is pair factor of 540]
• 540/18 = 30 [ 18 × 30 (18, 30) 18 and 30 is pair factor of 540]
• 540/20 = 27 [ 20 × 27 (20, 27) 20 and 27 is pair factor of 540]
• 540/27 = 20 [ 27 × 20 (27, 20) 27 and 20 is pair factor of 540]
• 540/30 = 18 [ 30 × 18 (30, 18) 30 and 18 is pair factor of 540]
• 540/36 = 15 [ 36 × 15 (36, 15) 36 and 15 is pair factor of 540]
• 540/45 = 12 [ 45 × 12 (45, 12) 45 and 12 is pair factor of 540]
• 540/54 = 10 [ 54 × 10 (54, 10) 54 and 10 is pair factor of 540]
• 540/60 = 9 [ 60 × 9 (60, 9) 60 and 9 is pair factor of 540]
• 540/90 = 6 [ 90 × 6 (90, 6) 90 and 6 is pair factor of 540]
• 540/108 = 5 [ 108 × 5 (108, 5) 108 and 5 is pair factor of 540]
• 540/135 = 4 [ 135 × 4 (135, 4) 135 and 4 is pair factor of 540]
• 540/180 = 3 [ 180 × 3 (180, 3) 180 and 3 is pair factor of 540]
• 540/270 = 2 [ 270 × 2 (270, 2) 270 and 2 is pair factor of 540]
• 540/540 = 1 [ 540 × 1 (540, 1) 540 and 1 is pair factor of 540]

As we checked numbers between 1 to 540 that are not leaving any remainder, hence we can say factors of 540 is 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270, 540.

Also note that, in exponential form prime factorization of 540 is written as 22 × 33 × 51 and it is a composite number.

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