# Prime factorization of 530

Here you will see step by step solution of prime factorization of 530, how to find factors of 530, you will see all factors of 530, how many factors of 530 has? Factors of 530 are 1, 2, 5, 10, 53, 106, 265, 530, we can see that 530 has 8 factor and sum of all factors is 972.

• All Factors of 530: 1, 2, 5, 10, 53, 106, 265, 530
• Prime Factors of 530: 2 × 5 × 53
• Prime Factorization of 530: 21 × 51 × 531
• Sum of Factors of 530: 972
• Is 530 prime number: No

### How to find factors of 530 by Division Method?

To find the factors of 530 by division method, we need the find the all numbers between 1 to 530, which divide 530 with 0 remainder, then the number is factor of 530.

### Pair factors of 530

• 530/1 = 530 [ 1 × 530 (1, 530) 1 and 530 is pair factor of 530]
• 530/2 = 265 [ 2 × 265 (2, 265) 2 and 265 is pair factor of 530]
• 530/5 = 106 [ 5 × 106 (5, 106) 5 and 106 is pair factor of 530]
• 530/10 = 53 [ 10 × 53 (10, 53) 10 and 53 is pair factor of 530]
• 530/53 = 10 [ 53 × 10 (53, 10) 53 and 10 is pair factor of 530]
• 530/106 = 5 [ 106 × 5 (106, 5) 106 and 5 is pair factor of 530]
• 530/265 = 2 [ 265 × 2 (265, 2) 265 and 2 is pair factor of 530]
• 530/530 = 1 [ 530 × 1 (530, 1) 530 and 1 is pair factor of 530]

As we checked numbers between 1 to 530 that are not leaving any remainder, hence we can say factors of 530 is 1, 2, 5, 10, 53, 106, 265, 530.

Also note that, in exponential form prime factorization of 530 is written as 21 × 51 × 531 and it is a composite number.

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